OOIP, OGIP, Recoverable Volume and Reserves: The Difference
Trace rock volume to oil or gas in place, separate an assumed recovery fraction from reserves classification, and work a volumetric OGIP example with clear units.
By PetroCalcHub Team | Updated 2026-10-24
Original diagram Interactive example Worked practice 3 technical sources
Engineering context
Original oil in place (OOIP) and original gas in place (OGIP) estimate how much petroleum an accumulation originally contained on a defined volume basis. A recovered quantity answers a further question about how much a stated process or project might produce. Reserves adds project and commercial requirements. These terms describe different information, so a larger calculator result is not automatically a larger reserves estimate.
The worked example builds a gas volume from rock geometry, porosity, initial water saturation and a compatible gas formation volume factor. It then applies a plainly hypothetical recovery fraction as separate arithmetic. The interactive control changes only that assumption. It does not assess a development project or assign a formal resources class. Use the official PRMS reference for those classifications.
1 · Rock
348,480,000 ft³
Area × net thickness
2 · Pores
52,272,000 ft³
Rock volume × porosity
3 · Gas-filled pores
39,204,000 reservoir ft³
Pore volume × (1 − Swi)
÷ Bgi → OGIP = 7.8408 billion scf
A physical estimate on a stated standard-gas basis.
Separate recovery assumption
60% × OGIP = 4.70448 billion scf
Assumed recovered quantity.
Additional project assessment
Discovery, recovery project, commercial evidence and evaluation date.
No reserves class supplied by this diagram.
Change one thing and observe the result
Keep A = 160 acres, h = 50 ft, porosity = 0.15, Swi = 0.25 and Bgi = 0.005 reservoir ft³/scf. Change only a hypothetical recovery fraction; it supplies no project or commercial evidence.
Resources/reserves classification: not assessed. The slider changes an arithmetic assumption, including at its 0% and 100% endpoints.
Practical workflow
- 1
State the reservoir geometry, pore fraction, initial saturation and compatible fluid volume factor.
- 2
Calculate the original surface-equivalent quantity while retaining each reservoir-volume conversion.
- 3
Keep a recovery assumption and its resulting volume on a separate line.
- 4
Use the official PRMS for project classification instead of relabeling the calculator output.
Start with rock volume and identify the occupied pores
Area multiplied by net thickness gives the rock volume included in a simple uniform reservoir model. With area in acres and thickness in feet, multiply by 43,560 to obtain cubic feet. For 160 acres and 50 ft, bulk rock volume is 348,480,000 ft³. This number includes the solid rock framework as well as its pore space; it is not a petroleum volume.
Multiply by porosity 0.15 to obtain 52,272,000 ft³ of pore volume. Under this example's initial gas-and-water occupancy assumption, water saturation 0.25 leaves gas occupying 75% of those pores. The initial gas-filled pore volume is therefore 39,204,000 reservoir ft³. The calculation does not establish net pay, spatial variability or saturation from raw measurements; those are supplied interpretations.
Convert reservoir gas volume to a stated surface basis
The initial gas formation volume factor Bgi relates gas volume at initial reservoir conditions to its volume at the stated standard conditions. Here Bgi is 0.005 reservoir ft³ per standard cubic foot. Dividing 39,204,000 reservoir ft³ by that factor gives 7,840,800,000 scf, or 7.8408 billion standard cubic feet. The reservoir-volume unit cancels, leaving a standard-condition gas volume.
Write the reference pressure and temperature behind the chosen standard cubic foot when preparing a real case. Also check the numerator units: a Bg supplied in reservoir barrels per scf cannot be entered unchanged into this cubic-foot form. The example treats the gas phase and its supplied Bgi consistently; it does not infer a gas composition or separator-product specification from a volumetric estimate.
Keep oil and gas in-place bases distinct
OOIP is commonly reported as a stock-tank oil volume, while OGIP is commonly reported as gas volume at specified standard conditions. Their formation volume factors relate different reservoir and surface volumes. A quantity stated in reservoir barrels, stock-tank barrels or standard cubic feet needs its label retained throughout the worksheet. The words 'in place' describe the original quantity being estimated, not the physical conditions of the reported unit.
An in-place estimate can also come from material balance when production, pressure and fluid data support the chosen model. The linked general oil material-balance calculator rearranges an oil balance using compatible withdrawal, influx and expansion terms. It estimates N on a stock-tank oil basis. That is a different calculation route from this gas geometry example, and it still does not independently determine a project's commercial recoverable quantity.
Apply a hypothetical recovery fraction on a separate line
For a teaching assumption of 60% recovery, multiply the calculated OGIP by 0.60. The result is 4.70448 billion scf of assumed recovered gas on the same volume basis. The remaining arithmetic complement is 3.13632 billion scf. Neither number is a forecast derived from a reservoir drive model; the recovery fraction is an input selected for this exercise.
Changing that fraction must leave the in-place estimate unchanged. The explorer keeps geometry, saturation and Bgi fixed so the distinction is visible. A recovery model for an actual accumulation would need additional information about its process, pressure behavior, displacement, wells and operating constraints. A convenient round percentage is not evidence that those conditions support that recovered volume.
| Assumed recovery | Assumed recovered (billion scf) | Arithmetic remainder (billion scf) |
|---|---|---|
| 40% | 3.13632 | 4.70448 |
| 60% | 4.70448 | 3.13632 |
| 80% | 6.27264 | 1.56816 |
Recognize the additional project question behind reserves
PRMS treats reserves as remaining quantities expected to be commercially recovered through defined development projects in known accumulations under stated conditions and at an evaluation date. Classification therefore calls for information about discovery, recoverability, commerciality and the project. The official document provides the detailed criteria. A geometric quantity and an assumed recovery percentage provide only part of that information.
For this synthetic case, no development project, costs, production schedule or commercial assessment has been supplied. The honest output label is 'assumed recovered volume at 60%,' followed by its gas basis. Do not attach a reserves category to the result or interpret the slider's low and high settings as proved, probable or possible volumes. The control explores arithmetic sensitivity rather than uncertainty categories or project maturity.
Make the boundary of the calculation easy to audit
Keep a short ledger that separates supplied reservoir inputs, calculated in-place volume and the separately assumed recovery fraction. Record the date and basis of each input interpretation. If a later model changes porosity, net thickness or Bgi, recalculate the in-place line before comparing recovered quantities. If only the assumed fraction changes, the original geometric estimate should remain the same.
Use a different worksheet for any project-based forecast and formal classification assessment. State whether a reported quantity concerns original or remaining petroleum, gas at standard conditions, or stock-tank liquid. This keeps a helpful educational calculation from acquiring an unsupported meaning as it moves into a slide deck or report. The linked calculators provide transparent physical arithmetic; their outputs need the surrounding case information to answer a project question.
From 160 acres to OGIP, then a separate recovery assumption
Use A = 160 acres, h = 50 ft, phi = 0.15, Swi = 0.25 and Bgi = 0.005 reservoir ft³/scf. Separately assume 60% recovery for illustration.
- 1. Calculate bulk rock volume43,560 × 160 × 50 = 348,480,000 ft³.
Convert acre-feet to the reservoir cubic-foot basis used by this equation.
- 2. Calculate initial gas-filled pore volume348,480,000 × 0.15 × (1 − 0.25) = 39,204,000 reservoir ft³.
Apply porosity, then the gas share of pore occupancy for the stated gas-water case.
- 3. Convert to OGIP39,204,000 / 0.005 = 7,840,800,000 scf.
Bgi removes the reservoir-volume unit and leaves the stated standard gas volume.
- 4. Apply the separate assumption7.8408 × 0.60 = 4.70448 billion scf assumed recovered.
The 60% multiplier is a teaching input; it does not classify the quantity as reserves.
Result
Calculated OGIP is 7.8408 billion scf. The separate 60% assumption gives 4.70448 billion scf as an assumed recovered volume.
Interpretation
The in-place line describes storage on the stated gas basis. Project recovery and classification require information beyond these inputs.
Test your understanding
Change the recovery assumption to 40% while holding all reservoir inputs fixed. Which result changes?
Show the worked answer
OGIP remains 7.8408 billion scf. Assumed recovered volume becomes 3.13632 billion scf, and the arithmetic remainder becomes 4.70448 billion scf. No resources class is assigned.
Method selection guide
Match the calculation method to the physical question and the evidence available.
| Condition | Use | Why |
|---|---|---|
| You have geometry, initial saturation and gas Bgi | Calculate volumetric OGIP | Those inputs support the stated initial gas-volume account. |
| You want to explore an assumed recovery fraction | Keep the multiplier and result explicitly hypothetical | The calculation does not establish the recovery mechanism or project evidence. |
| You need a formal resources or reserves classification | Apply the governing project-based evaluation framework | PRMS classification requires additional information beyond in-place arithmetic. |
Before using the result
- Use net reservoir geometry and state its interpretation.
- Enter porosity and initial saturation as fractions.
- Match Bgi's reservoir-volume numerator to the equation.
- Record the standard-condition gas or stock-tank oil basis.
- Label recovery fractions as supplied assumptions unless supported by a separate model.
- Keep original, recovered, remaining and formally classified quantities distinct.
Start with these calculators
These links keep the guide close to the working calculator flow.