PetroCalcHub

Engineering lesson

Measured depth and diameter checks for a volume calculation

Volume uses measured interval length and the actual enclosing and enclosed diameters. TVD is appropriate for hydrostatic head, but it generally understates volume in a deviated interval.

By PetroCalcHub Team · Updated October 24, 2026 · Free to read and use

Audit length and diameter before arithmetic

An annular interval extends along the well path. Its volume is area times measured length. A 1,000 ft path that gains only 600 ft of TVD still contains the full 1,000 ft of annular space.

The diameters must describe the fluid boundaries. An outer casing's nominal size is not its ID; an inner casing's ID is not its OD. Keep these labels on the interval sketch.

Make impossible inputs fail visibly

The outer boundary diameter must exceed the inner diameter. Equal values give zero idealized area, while an inverted pair is physically invalid for the stated annulus.

Check diameter units before squaring them. Mixing inches and millimetres creates a large error that multiplication by the correct length cannot repair.

Use a section ledger when geometry changes

A change in hole size, casing ID, string OD or measured interval boundary creates a new geometric entry. Do not average diameters before squaring; the average of squared diameters differs from the square of their average.

A schematic constant-area calculation also assumes no obstruction or internal equipment occupying additional space. Record any separately added or subtracted volume.

Hole diameter / outer IDFluid areaPipe ODA = π(D² − d²)/4
The fluid occupies the area between boundaries. Multiply by measured interval length for volume; divide actual flow rate by this area for average speed. Schematic, not to scale.

Explore the example

Original synthetic teaching calculation. Equations and fixed controls are stated here; these are not field measurements.

1,000

Select one of 5 recorded scenarios. Intermediate states are not interpolated.

Selected scenario

Measured length (ft) = 1000. Annular volume (bbl): 45.9; Capacity (bbl/ft): 0.0459.

Selected result045.991.82501,1302,000Scenario input
  • Annular volume (bbl)
Annular volume (bbl) versus Measured length (ft). Green marks the selected row. Lines connect recorded points for orientation; exact solved values are tabulated below.

Worked example

Capacity multiplied by measured length

8.5 in hole around 5 in casing; the rounded library coefficient gives 0.0459 bbl/ft capacity.

Relation and unit basis

Va = 0.7854(Dh² − Do²)L/808.5

Diameters in inches, measured length in feet, volume in petroleum barrels. Capacity is Va/L.

  1. 1. Define the baseline

    Measured length (ft) = 1000

    8.5 in hole around 5 in casing; the rounded library coefficient gives 0.0459 bbl/ft capacity.

  2. 2. Select the relation

    Va = 0.7854(Dh² − Do²)L/808.5

    Diameters in inches, measured length in feet, volume in petroleum barrels. Capacity is Va/L.

  3. 3. Substitute the values

    0.7854 × (8.5² − 5²) × 1,000/808.5 = 45.9 bbl

    Retain intermediate precision. The displayed values are rounded only after evaluation.

  4. 4. Read the result

    Annular volume (bbl) = 45.9; Capacity (bbl/ft) = 0.0459

    Length changes volume, while capacity is unchanged at fixed diameters.

Result and interpretation

Annular volume (bbl) = 45.9; Capacity (bbl/ft) = 0.0459

Length changes volume, while capacity is unchanged at fixed diameters.

The length sweep illustrates measured path length at one fixed cross section; it is not a depth-pressure plot.

Exact scenario data

Original synthetic teaching calculation. Equations and fixed controls are stated here; these are not field measurements.

Exact recorded values for Capacity multiplied by measured length. Units are included in the headers.
Measured length (ft)Annular volume (bbl)Capacity (bbl/ft)
25011.4750.0459
50022.950.0459
1,00045.90.0459
1,50068.850.0459
2,00091.80.0459

Scroll the table to see all columns. The highlighted row is the worked baseline. Downloads retain full numerical precision.

Test your understanding

Work through the question before revealing its answer. Use the stated assumptions and include units in every numerical step.

  1. 1. At capacity 0.0459 bbl/ft, how much does using 600 ft TVD instead of 1,000 ft MD omit?

    Show the worked answer

    18.36 bbl: (1,000 − 600) × 0.0459. That is 40% of the correct 45.9 bbl.

  2. 2. Reproduce the baseline Annular volume (bbl) without rounding intermediate values.

    Show the worked answer

    0.7854 × (8.5² − 5²) × 1,000/808.5 = 45.9 bbl. Annular volume (bbl) = 45.9. Length changes volume, while capacity is unchanged at fixed diameters.

  3. 3. Compare the first and last recorded scenarios. Which input changes?

    Show the worked answer

    Measured length (ft) changes from 250 to 2000. Other controls remain as stated in the premise. Annular volume (bbl) changes from 11.475 to 91.8.

  4. 4. What would be needed to apply this example to a different physical system?

    Show the worked answer

    Replace the synthetic controls with compatible documented inputs and check the relation's assumptions. Diameters in inches, measured length in feet, volume in petroleum barrels. Capacity is Va/L. Length changes volume, while capacity is unchanged at fixed diameters.

Before using the result

  • Use measured interval length.
  • Check each ID and OD label.
  • Convert all diameters before squaring.

Length changes volume, while capacity is unchanged at fixed diameters.

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Sources and method

The explanation and synthetic examples are original PetroCalcHub teaching material. The references below support the definitions and model context. They do not supply field validation for the synthetic scenarios.

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