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Production EngineeringWell Performance

Haaland Darcy Friction Factor

fD=[−1.8log⁡10A]−2A=(ε/D3.7)1.11+6.9Re\begin{aligned}f_D&=[-1.8\log_{10}A]^{-2}\\A&=\left(\frac{\varepsilon/D}{3.7}\right)^{1.11}+\frac{6.9}{\mathrm{Re}}\end{aligned}

Tabular solver

Run the same equation across multiple cases and compare results in one table.

CaseRedimensionlesseps_DdimensionlessResultAction
1Pending
2Pending
3Pending