Transmissibility Between Tight Gas Compartments Formula
Transmissibility Between Tight Gas Compartments calculates transmissibility between compartments for unconventional reservoirs workflows in reservoir engineering.
How engineers use this formula
Use this formula when the listed inputs (gamma_a, gamma_b, L_1, L_2) are known and the assumptions behind the cited unconventional reservoirs relationship match the engineering case being checked.
Assumptions
- Input values are representative for the well, reservoir, fluid, or equipment case being evaluated.
- The declared units match the field-unit constants used in the formula.
- The cited formula applies to the selected petroleum engineering workflow.
Limitations
- The calculation does not replace a full engineering model or operating procedure.
- Accuracy depends on the source correlation, assumptions, input quality, and unit consistency.
Common mistakes
- Mixing unit systems without converting the inputs.
- Using default example values as field recommendations.
- Applying the formula outside the source assumptions.
Default example
Using the default inputs, gamma equals 375 mD*ft^2/cP.
600
300
100
150
Inputs
gamma_a
mD*ft^2/cPTransmissibility of compartment 1
gamma_b
mD*ft^2/cPTransmissibility of compartment 2
L_1
ftLength of compartment 1
L_2
ftLength of compartment 2
Outputs
gamma
Transmissibility between compartments
gamma_a
Transmissibility of compartment 1
gamma_b
Transmissibility of compartment 2
L_1
Length of compartment 1
L_2
Length of compartment 2
Source and review
reviewedAhmed, T. and McKinney, P. D. 2015. Advanced Reservoir Engineering, Gulf Publishing Elsevier, Chapter 3, Page 236.
Source