Reservoir EngineeringThermal Gradients
Thermal Conductivity from Heat Flow Formula
Thermal Conductivity from Heat Flow calculates thermal conductivity for thermal gradients workflows in reservoir engineering.
How engineers use this formula
Use this formula when the listed inputs (Q, L, A, Delta_T) are known and the assumptions behind the cited thermal gradients relationship match the engineering case being checked.
Assumptions
- Input values are representative for the well, reservoir, fluid, or equipment case being evaluated.
- The declared units match the field-unit constants used in the formula.
- The cited formula applies to the selected petroleum engineering workflow.
Limitations
- The calculation does not replace a full engineering model or operating procedure.
- Accuracy depends on the source correlation, assumptions, input quality, and unit consistency.
Common mistakes
- Mixing unit systems without converting the inputs.
- Using default example values as field recommendations.
- Applying the formula outside the source assumptions.
Default example
Using the default inputs, k_thermal equals 0.5 BTU/(ft*s*K).
QBTU/s
100
Lft
10
Aft2
50
Delta_TK
40
Inputs
Q
BTU/sHeat Flow Rate
L
ftConduction Length
A
ft2Cross-Sectional Area
Delta_T
KTemperature Difference
Outputs
k_thermal
BTU/(ft*s*K)
Thermal Conductivity
Q
BTU/s
Heat Flow Rate
L
ft
Conduction Length
A
ft2
Cross-Sectional Area
Delta_T
K
Temperature Difference
Source and review
reviewedTransport Phenomena, Bird, R.B., Stewart, W.E., Lightfoot, E.N. (2002)
Bird, R.B., Stewart, W.E. and Lightfoot, E.N. 2002. Transport Phenomena, 2nd ed., Chapter 9, Page 266.
Source