Payne Intercompartmental Gas Flow in Tight Gas Reservoirs Formula
Payne Intercompartmental Gas Flow in Tight Gas Reservoirs calculates gas flow rate from compartment 1 to compartment 2 for unconventional reservoirs workflows in reservoir engineering.
How engineers use this formula
Use this formula when the listed inputs (k, A, T, L, mP_1, mP_2) are known and the assumptions behind the cited unconventional reservoirs relationship match the engineering case being checked.
Assumptions
- Input values are representative for the well, reservoir, fluid, or equipment case being evaluated.
- The declared units match the field-unit constants used in the formula.
- The cited formula applies to the selected petroleum engineering workflow.
Limitations
- The calculation does not replace a full engineering model or operating procedure.
- Accuracy depends on the source correlation, assumptions, input quality, and unit consistency.
Common mistakes
- Mixing unit systems without converting the inputs.
- Using default example values as field recommendations.
- Applying the formula outside the source assumptions.
Default example
Using the default inputs, Q_12 equals 1,076.192308 SCF/day.
0.01
1000
520
100
300000000
250000000
Inputs
k
mDPermeability between compartments
A
ft^2Cross-sectional flow area
T
deg RReservoir temperature
L
ftDistance between compartment centers
mP_1
psi^2/cPGas pseudopressure in compartment 1
mP_2
psi^2/cPGas pseudopressure in compartment 2
Outputs
Q_12
Gas flow rate from compartment 1 to compartment 2
k
Permeability between compartments
A
Cross-sectional flow area
T
Reservoir temperature
L
Distance between compartment centers
mP_1
Gas pseudopressure in compartment 1
mP_2
Gas pseudopressure in compartment 2
Source and review
reviewedAhmed, T. and McKinney, P. D. 2005. Advanced Reservoir Engineering, Gulf Publishing of Elsevier, Chapter 3, Pages 234-235.
Source