Drilling EngineeringDrilling Hydraulics
Pump Pressure Exponent from Two Pump Tests Formula
Pump Pressure Exponent from Two Pump Tests calculates pump pressure exponent for drilling hydraulics workflows in drilling engineering.
How engineers use this formula
Use this formula when the listed inputs (P_1, P_2, Q_1, Q_2) are known and the assumptions behind the cited drilling hydraulics relationship match the engineering case being checked.
Assumptions
- Input values are representative for the well, reservoir, fluid, or equipment case being evaluated.
- The declared units match the field-unit constants used in the formula.
- The cited formula applies to the selected petroleum engineering workflow.
Limitations
- The calculation does not replace a full engineering model or operating procedure.
- Accuracy depends on the source correlation, assumptions, input quality, and unit consistency.
Common mistakes
- Mixing unit systems without converting the inputs.
- Using default example values as field recommendations.
- Applying the formula outside the source assumptions.
Default example
Using the default inputs, n equals 1.87214 dimensionless.
P_1psi
2700
P_2psi
500
Q_1gpm
320
Q_2gpm
130
Inputs
P_1
psiCirculating Pressure at Rate 1
P_2
psiCirculating Pressure at Rate 2
Q_1
gpmPump Rate 1
Q_2
gpmPump Rate 2
Outputs
n
dimensionless
Pump Pressure Exponent
P_1
psi
Circulating Pressure at Rate 1
P_2
psi
Circulating Pressure at Rate 2
Q_1
gpm
Pump Rate 1
Q_2
gpm
Pump Rate 2
Source and review
reviewedDrillingFormulas. Calculate Pump Pressure and Select Most Suitable Pump Exponent.
Source