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Geomechanics and FracturingNaturally Fractured Reservoirs

Average Fracture Spacing from Linear Intensity Formula

Sf=1P10S_f=\frac{1}{P_{10}}

Average Fracture Spacing from Linear Intensity calculates average fracture spacing for naturally fractured reservoirs workflows in geomechanics and fracturing.

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How engineers use this formula

Use this formula when the listed inputs (P10) are known and the assumptions behind the cited naturally fractured reservoirs relationship match the engineering case being checked.

Assumptions

  • Input values are representative for the well, reservoir, fluid, or equipment case being evaluated.
  • The declared units match the field-unit constants used in the formula.
  • The cited formula applies to the selected petroleum engineering workflow.

Limitations

  • The calculation does not replace a full engineering model or operating procedure.
  • Accuracy depends on the source correlation, assumptions, input quality, and unit consistency.

Common mistakes

  • Mixing unit systems without converting the inputs.
  • Using default example values as field recommendations.
  • Applying the formula outside the source assumptions.

Default example

Using the default inputs, S_f equals 4 ft.

P101/ft

0.25

Inputs

P10

1/ft

Linear Fracture Intensity

Outputs

S_f

ft

Average Fracture Spacing

P10

1/ft

Linear Fracture Intensity

Source and review

reviewed

TU Bergakademie Freiberg. Characterization and fluid transport simulations of fractures and fracture networks, Section 2.2.3.

Source

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