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API RP 14E Two-Phase Flowline Pressure Drop Formula

ΔP100=0.000336fW2Di5ρm\Delta P_{100}=\frac{0.000336fW^2}{D_i^5\rho_m}

API RP 14E Two-Phase Flowline Pressure Drop calculates two-phase flowline pressure drop per 100 ft for well performance workflows in production engineering.

Calculate

How engineers use this formula

Use this formula when the listed inputs (f, W, D_i, rho_m) are known and the assumptions behind the cited well performance relationship match the engineering case being checked.

Assumptions

  • Input values are representative for the well, reservoir, fluid, or equipment case being evaluated.
  • The declared units match the field-unit constants used in the formula.
  • The cited formula applies to the selected petroleum engineering workflow.

Limitations

  • The calculation does not replace a full engineering model or operating procedure.
  • Accuracy depends on the source correlation, assumptions, input quality, and unit consistency.

Common mistakes

  • Mixing unit systems without converting the inputs.
  • Using default example values as field recommendations.
  • Applying the formula outside the source assumptions.

Default example

Using the default inputs, DeltaP_100 equals 3.9896 psi/100 ft.

fdimensionless

0.0196

Wlb/hr

46482.8

D_iin

3.15

rho_mlb/ft3

11.5

Inputs

f

dimensionless

Moody Friction Factor

W

lb/hr

Total Liquid Plus Vapor Weight Flow Rate

D_i

in

Pipe Inside Diameter

rho_m

lb/ft3

Gas-Liquid Mixture Density

Outputs

DeltaP_100

psi/100 ft

Two-Phase Flowline Pressure Drop per 100 ft

f

dimensionless

Moody Friction Factor

W

lb/hr

Total Liquid Plus Vapor Weight Flow Rate

D_i

in

Pipe Inside Diameter

rho_m

lb/ft3

Gas-Liquid Mixture Density

Source and review

reviewed

API RP 14E Section 2.5 pressure-drop equation for gas/liquid two-phase steel piping.

Source

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