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Reservoir EngineeringWell Performance

Effective Wellbore Radius of a Horizontal Well – Method 1 (Anisotropic Reservoirs)

rwd=rehL2a(1+1(L2a)2)(βh2rw)βhLr_{wd} = \frac{r_{eh} \cdot \frac{L}{2}}{a \cdot \left(1 + \sqrt{1 - \left(\frac{L}{2a}\right)^2}\right) \cdot \left(\frac{\beta h}{2r_w}\right)^{\frac{\beta h}{L}}}

Tabular solver

Run the same equation across multiple cases and compare results in one table.

CaseAacresLftk_hmdk_vmdhftr_wftResultAction
1Pending
2Pending
3Pending